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Self-replicating manufacturing

How thick must a printer rod be to keep carriage ringing small at a given acceleration?

research/selfrep-alufring

Rod diameter from an acceleration and ringing budget: at 3 m/s² with abrupt steps steel needs 7.3 mm, aluminium 9.6 mm, hardwood 15.5 mm; a 20 ms force ramp cuts aluminium at 5 m/s² from 10.9 to 8.9 mm (stylised).

6 tests

What it found

Follow-up to selfrep-alufreq: the rod diameter is derived from an acceleration and a 50 µm ringing tolerance (one-mode oscillator, assumed 0.3 kg carriage and damping ratio 0.01) instead of a bare frequency target. At 3 m/s² with abrupt steps steel needs 7.3 mm, aluminium 9.6 mm and hardwood 15.5 mm; ramping the force over 20 ms cuts aluminium at 5 m/s² from 10.9 to 8.9 mm. Stylised: one mode, assumed damping, nothing measured.

A figure from its own output

Figure produced by research/selfrep-alufring: diameter_vs_accel
selfrep-alufring/experiments/diameter_vs_accel.svg, written by the project's own experiment code.

Paper, code and results

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Produced with AI assistance (Claude). Results are from the code in this repository and are simulated or stylised unless the abstract says otherwise; nothing here implies affiliation with or endorsement by any lab, researcher or company cited. MIT licensed.