How should a server weight workers that ran different numbers of inner steps?
research/heterogeneous-steps
Weighting workers that ran different numbers of inner steps: exact floor α²Σw²V/(r(2−r)), worker information I∞·tanh(λH/2) saturates, optimal weights span ≤2× so equal weights lose ≤9/8 (measured ≤1.09) while step-proportional weights lose up to 1.76× per mode and 10.5× on three modes.
What it found
With worker i running Hi steps, weighted averaging has exact floor α2Σwi2Vi/(r(2−r)), r = αΣwisi. One worker's information is I∞tanh(λH/2): H=8 carries 20% of the ceiling and H=64 93%, so a fast device is worth far less than its step count. Information-optimal weights span at most 2×, hence equal weights lose at most 9/8 (measured ≤1.09), whereas step-proportional (FedAvg-style) weights lose up to 1.76× per mode and 10.5× on three modes when one worker in eight is 256× faster. Matched to simulation within 1%. Stylised: quadratic, shared optimum (no client drift), fixed Hi.
A figure from its own output
Paper, code and results
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Produced with AI assistance (Claude). Results are from the code in this repository and are simulated or stylised unless the abstract says otherwise; nothing here implies affiliation with or endorsement by any lab, researcher or company cited. MIT licensed.